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ILL GIVE BRAINLIEST A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y = –0.02x2 + 2.3x + 6, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land?
A. 57.50 m
B. 115.00 m
C. 117.55 m
D. 235.10 m

Respuesta :

the answer is C
hope this helps :)

Answer:

c)

Step-by-step explanation:

Simplifying

y = -0.02x2 + x + 2


Reorder the terms:

y = 2 + x + -0.02x2


Solving

y = 2 + x + -0.02x2


Solving for variable 'y'.


Move all terms containing y to the left, all other terms to the right.


Simplifying

y = 2 + x + -0.02x2

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