Answer with explanation:
→The given curve is Quadratic,having two real roots,as it cuts X axis at two distinct points that is at ,-2 and -4.
→Graph is symmetrical about line , x=-3.
→This curve is a Parabola,opening in upward direction ,that is having Y axis as Axis of Symmetry.
→Parabola is defined as locus of all the points such that distance from fixed point called focus, to distance from fixed line called Directrix ,is always Constant.
→Point which divides PARABOLA in two symmetrical parts is called Vertex having coordinates (-3,-1).
Equation of parabola having vertex ,(-3,-1) and opening in Upward Direction,that is in vertical direction, is given by:
General Equation: Equation of parabola passing through point (a,b) and opening in upward direction and having focus (k,h) is
y-b=4 k× (x-a)²
So, the equation of parabola will be
→y-(-1)=4 k[x-(-3)]²
→y+1==4 k(x+3)²-----(1)
This parabola also passes through (-4,0) and (-2,0).
→0+1=4 k×(-4+3)²
→1=4 k×(-1)²
[tex]1=4 k\\\\k=\frac{1}{4}[/tex]
If you will substitute , x=-2 and y=0 in equation 1,you will get same value of k.
Equation of Parabola ,that is equation 1,can be written as
[tex]y+1=4\times\frac{1}{4}(x+3)^2\\\\y+1=(x+3)^2\\\\ y=(x+3)^2-1[/tex]
Option B: y=(x+3)²-1
