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f(x) = cos(x)
f'(x) = -sin(x)
f'(π/2) = -sin(π/2)
f'(π/2) = -1

My answer to this question is A. -1, but I am posting it here because several students got B. +1 as their answer. Can anyone confirm the answer as A?

fx cosx fx sinx fπ2 sinπ2 fπ2 1 My answer to this question is A 1 but I am posting it here because several students got B 1 as their answer Can anyone confirm t class=

Respuesta :

sqdancefan
Your working out is correct. The appropriate answer is ...
  A. -1

For confirmation, check a graph of cos(x) at π/2. It has negative slope at that point.
Ver imagen sqdancefan
Your answer would be -1. 

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