Answer:[tex]W=1.304\times 10^{-19} J[/tex]
Explanation:
Given
Distance between two electron is [tex](r_1)5.3 nm[/tex]
Charge of electron[tex]=1.6\times 10^{-19} C[/tex]
Final distance[tex](r_2)=\farc{r_1}{4}=1.325 nm[/tex]
Work done[tex]=kq_1q_2\left ( \frac{1}{r_2}-\frac{1}{r_1}\right )[/tex]
[tex]W=\frac{1}{4\pi \epsilon _}q_1q_2\left ( \frac{1}{r_2}-\frac{1}{r_1}\right )[/tex]
[tex]W=9\times 10^9\times (1.6\times 10^{-19})^2\left ( \frac{1}{1.325\times 10^{-9}}-\frac{1}{5.3\times 10^{-9}}\right )[/tex]
[tex]W=9\times 10^9\times 2.56\times 10^{-38}\times 5.66\times 10^8 J[/tex]
[tex]W=1.304\times 10^{-19} J[/tex]
