Answer:
Final temperature of object = 25°C
Explanation:
Given data:
Final temperature of object = ?
Mass of object = 10 g
Specific heat capacity of object = 1 cal/g.°C
Heat content = 50 cal
Initial temperature = 20°C
Solution;
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
Now we will put the values in formula.
50 cal = 10 g × 1 cal/g.°C × (T2 - 20°C)
50 cal/ 10 cal/°C = (T2 - 20°C)
5 °C = (T2 - 20°C)
5°C + 20°C = T2
T2 = 25°C
