Answer:
Option B.
C₆H₁₀O₅ + 6O₂ —> 6CO₂ + 5H₂O
Explanation:
To know which option is correct, we shall write the balanced equation for the combustion of cellulose. This is illustrated below:
C₆H₁₀O₅ + O₂ —> CO₂ + H₂O
There are 6 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 6 before CO₂ as shown below:
C₆H₁₀O₅ + O₂ —> 6CO₂ + H₂O
There are 10 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 5 before H₂O as shown below:
C₆H₁₀O₅ + O₂ —> 6CO₂ + 5H₂O
There are a total of 7 atoms of O on the left side and a total of 17 atoms on the right side. It can be balance by writing 6 before O₂ as shown below:
C₆H₁₀O₅ + 6O₂ —> 6CO₂ + 5H₂O
Now, the equation is balanced.
Thus, option B gives the correct answer to the question.
