The Hawaiian language has 12 letters: five vowels and seven consonants. Each of the 12 Hawaiian letters are written on a slip of paper and placed in the bag. A letter is randomly chosen from the bag and then replaced. Then, a second letter is randomly chosen from the bag. What is the probability that two vowels are chosen?

Respuesta :

12 total letters...5 vowels and 7 consonants.

probability of 1st letter being a vowel is 5/12
after replacing ...
probability of 2nd letter being a vowel is 5/12

probability of both occurring is (5/12 * 5/12) = 25/144 <===


To solve the problem, the concept of replacement must be considered.

A letter is randomly chosen from the bag and then replaced. Then, a second letter is randomly chosen from the bag.

The probability of the two vowels chosen is 25/144.

What is probability?

Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1. Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.

Given

The Hawaiian language has 12 letters.

Five vowels and seven consonants.

To find

The probability of two vowels is chosen.

1.  Probability of first letter being vowel.

Total event = 12

Favorable event = 5

Then

[tex]\rm P_1 = \dfrac{5}{12}[/tex]

2.  Probability of second letter being vowel.

Total event = 12

Favorable event = 5

Then

[tex]\rm P_2 = \dfrac{5}{12}[/tex]

The probability of both occurring will be

[tex]\rm P = P_1 *P_2\\\\P = \dfrac{5}{12} * \dfrac{5}{12}\\\\P = \dfrac{25}{144}[/tex]

Thus, The probability of the two vowels chosen is 25/144.

More about the probability link is given below.

https://brainly.com/question/795909