[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$9000\\ P=\textit{original amount deposited}\\ r=rate\to 8.5\%\to \frac{8.5}{100}\dotfill &0.085\\ t=years\dotfill &12 \end{cases} \\\\\\ 9000=Pe^{0.085\cdot 12}\implies 9000Pe^{1.02}\implies \cfrac{9000}{e^{1.02}}=P\implies 3245.35\approx P[/tex]
