Answer:
[tex]2x^2+7x-1=0[/tex]
the value of [tex]b^2-4ac[/tex] is 57
Step-by-step explanation:
[tex]1 = 2x^2 + 7x[/tex]
Standard form of a quadratic equation is [tex]ax^2+bx+c=0[/tex]
Subtract 1 on both sides to get the standard form of the equation.
[tex]2x^2+7x-1=0[/tex]
Now we find the value of [tex]b^2-4ac[/tex]
From the standard form, the value of a=2, b=7, c=-1
the value of [tex]b^2-4ac=(7)^2-4(2)(-1)=49+8=57[/tex]
the value of [tex]b^2-4ac[/tex] is 57
