Answer : We can produce 125.7 g of [tex] S_{8} [/tex].
Explanation : The reaction will be
[tex]8SO_{2} + 16H_{2}S -----> 3S_{8} + 16H_{2}O[/tex]
The molecular mass of [tex]SO_{2}[/tex] is 64.1 g/mol
and molecular mass of [tex]H_{2}S [/tex] is 34.1 g/mol
For every mole of [tex]SO_{2}[/tex] we would need twice of [tex]H_{2}S [/tex] moles, so for every 3 moles of [tex] S_{8} [/tex] we need 16 moles of [tex]H_{2}S [/tex]
Now, we can calculate number of moles [tex] S_{8} [/tex]
2.61 X (3/16) = 0.49 moles
Here, the molecular mass of [tex] S_{8} [/tex] is 256.8 g
multiplying it with the number of 0.49 moles we get, 256.8 X 0.49 = 125.7 g of [tex] S_{8} [/tex].
Hence, 125.7 g of [tex] S_{8} [/tex] will be produced.
