[tex]\frac{7}{9} -\frac{2}{8} \times \frac{4}{9}[/tex]
Start by multiplying the fractions together. When multiplying fractions they don't need to have a common denominator, so multiply 2/8 and 4/9 from left to right.
[tex]\frac{2}{8} \times \frac{4}{9} = \frac{8}{72}[/tex]
Now your new problem looks like: 7/9 - 8/72. When subtracting fractions they have to have common denominators so multiply 7/9 by 8/8.
[tex]\frac{7}{9} \times \frac{8}{8}= \frac{56}{72}[/tex]
You can now subtract 56/72 and 8/72 to get your final answer.
[tex]\frac{56}{72} -\frac{8}{72} = \frac{48}{72}[/tex]
This fraction can be simplified by dividing both sides by 8 because the numerator and denominator of this fraction are multiples of 8 and can be divided evenly by 8.
[tex]\frac{48}{72} \div \frac{8}{8} = \frac{6}{9}[/tex]
6/9 can be simplified even further by dividing both sides by 3 because both 6 and 9 can be divided evenly by 3.
[tex]\frac{6}{9} \div \frac{3}{3} = \frac{2}{3}[/tex]
D) 2/3 is your final answer.
