Horizontal speed of the ball is given as
[tex]v_x = 4 m/s[/tex]
height of the ball is given as
[tex]h = 500 m[/tex]
now the time taken by the ball to reach the bottom is given as
[tex]h = v_i*t + \frac{1}{2}gt^2[/tex]
now we will plug in all values
[tex]500 = 0 + \frac{1}{2}*9.8*t^2[/tex]
[tex]t = 10.1 s[/tex]
now the distance from the base is given as
[tex]x = v_x * t[/tex]
`[tex]x = 4 * 10.1 = 40.4 m[/tex]
so it will land at distance of 40.4 m
