Answer:
Displacement in Y direction is 0.434 m
Explanation:
initial velocity of the puck is 2.35 m/s at -22 degree
so here it is given as
[tex]v_i = 2.35 cos22 \hat i - 2.35 sin22 \hat j[/tex]
[tex]v_i = 2.18 \hat i - 0.88 \hat j[/tex]
final velocity is given as 6.42 m/s at 50 degree
so we have
[tex]v_f = 6.42 cos50 \hat i + 6.42 sin50\hat j[/tex]
[tex]v_f = 4.13 \hat i + 4.92\hat j[/tex]
now displacement in Y direction is given as
[tex]\Delta y = \frac{v_f + v_i}{2}t[/tex]
[tex]\Delta y = \frac{-0.88 + 4.92}{2} (0.215)[/tex]
[tex]\Delta y = 0.434 m[/tex]
