By substitution: Equation 2 says [tex]y=\dfrac23x-2[/tex], so in equation 1 we have
[tex]2\left(\dfrac23x-2\right)=3x-5[/tex]
[tex]\dfrac43x-4=3x-5[/tex]
[tex]4x-12=9x-15[/tex]
[tex]5x=3[/tex]
[tex]x=\dfrac35[/tex]
Then [tex]y=\dfrac23x-2[/tex] says
[tex]y=\dfrac23\left(\dfrac35\right)-2=\dfrac25-2=-\dfrac85[/tex]
