At a game show, there are 6 people (including you and your friend) in the front
row
The host randomly chooses 3 people from the front row to be contestants.
The order in which they are chosen does not matter
There are 6C3 20 total ways to choose the 3 contestants
What is the probability that you a your friend are both chosen?

a. 3/20
b.4/20
c.2/20
d.2/3​

Respuesta :

Answer: 4/20

Step-by-step explanation:

Option b is correct. The probability that you and your friend are both chose is 4/20.

What is probability?

The probability provides a means of getting an idea of likelihood of occurrence of different events resulting from a random experiment in terms of quantitative measures ranging between zero and one.

Formula for probability

P(E) = number of favorable outcomes/Total number of outcomes

Where,

P(E) is the probability of an event.

What is combination?

An arrangement of objects where the order in which the objects are selected does not matter is called combination.

Combination Formula

[tex]C_{n,k} = \frac{n!}{(n-k)!k!}[/tex]

Where,

n is total number of objects in set

[tex]C_{n, k}[/tex] is number of combinations

k is number of choosing objects from the set

According to the given question

We have

Total six people.

And,

There are total [tex]6C_{3}[/tex]  ways to choose the 3 contestants.

⇒ [tex]6C_{3} = \frac{6!}{(6-3)!3!}[/tex] = [tex]\frac{(6)(5)(4)(3!)}{(3!)(3!)}[/tex] = 20

total number of outcomes = 60

⇒ There are 20 ways to select 3 contestant among 20 people.

Now, the number of ways that, you and your friend are chosen, along with 1 person from a set of 4 is given by

[tex]C_{4,1} = \frac{4!}{1!3!}= 4[/tex]

total number of favorable outcomes = 4

Therefore,

The probability that you and your friend are both chose = [tex]\frac{4}{20}[/tex]

Hence, option b is correct.

Learn more about probability and combination here:

https://brainly.com/question/11234257

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