Answer:
The hypotenuse is 5, the sides are 3 and 4. The perimeter is the addition of those 3 numbers.
5+4+3 = 12 units
For future reference, if the sides of a right triangle are any multiples of 3 and 4, the hypotenuse is the same multiple of 5. This triangle has sides with lengths 3, 4, and 5, and a triangle with sides 9 and 12 would have a hypotenuse of 15 :)
Step-by-step explanation:
Answer:
12 units is the perimeter of triangle ABC.
Step-by-step explanation:
Coordinates of triangle ABC:
A = (-1,3), B = (3,6), C = (3,3)
Distance formula: [tex](x_1,y_1),(x_2,y_2)[/tex]
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Distance of AB: A = (-1,3), B = (3,6)
[tex]AB=\sqrt{(3-(-1))^2+(6-3)^2}[/tex]
[tex]AB=\sqrt{(4)^2+(3)^2}=5 units[/tex]
Distance of BC: B = (3,6) , C = (3,3)
[tex]BC=\sqrt{(3-3)^2+(3-6)^2}[/tex]
[tex]BC=\sqrt{(0)^2+(-3)^2}=3 units[/tex]
Distance of CA: C = (3,3) , A = (-1,3)
[tex]CA=\sqrt{((-1)-3)^2+(3-3)^2}[/tex]
[tex]CA=\sqrt{(-4)^2+(0)^2}=4 units[/tex]
Perimeter of the triangle ABC = AB +BC + CA
= 5 units + 3 units + 4 units = 12 units
12 units is the perimeter of triangle ABC.
