The velocity of the ping-pong ball must be 8109 m/s
Explanation:
The momentum of an object is given by
[tex]p=mv[/tex]
where
m is the mass of the object
v is its velocity
For the bowling ball, we have
m = 9 kg
v = 3.28 m/s
so its momentum is
[tex]p=(9)(3.28)=29.5 kg m/s[/tex]
We want the ping-pong ball to have the same momentum, so:
p' = 29.5 kg m/s
And the mass of the ping-pong ball is
m = 3.638 g = [tex]3.638\cdot 10^{-3} kg[/tex]
Therefore, its velocity must be:
[tex]v=\frac{p}{m}=\frac{29.5}{3.638\cdot 10^{-3}}=8109 m/s[/tex]
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