Respuesta :
Answer:
68.26% corresponds to the life span of fruit flies that are between 29 days and 37 days
Step-by-step explanation:
Given that the life span of a species of fruit fly have a bell-shaped distribution, with a mean of 33 days and a standard deviation of 4 days.
Let X be the life span
X is N(33,4)
we can convert X into Z standard normal variate by
[tex]z=\frac{x-33}{4}[/tex]
To find the percentage corresponds to the life span of fruit flies that are between 29 days and 37 days
For this let us find probability for x lying between 29 and 37 days
[tex]29\leq x\leq 37\\=-1\leq z\leq 1[/tex]
Probability = P(|z|<1) = 0.6826
Convert to percent
68.26% corresponds to the life span of fruit flies that are between 29 days and 37 days
