Answer:
The order of this half-life reaction is zero. This is a zero order reaction.
Explanation:
Step 1: Data given
At the pressure P0,1 of 55.5 kPa, the half-life is 340 s
At the pressure P0,2 of 28.9 kPa, the half-life is 178 s
Step 2: Calculate the order
(n-1) = ((log (t1/2P0,1 / t1/2P0,2)) / (log (P0,2 /P0,1)))
⇒ with t1/2P0,1 = the half-life at a pressure of 55.5 kPa = 340 s
⇒ with t1/2P0,2 = the half-life at a pressure of 28.9 kPa = 178 s
⇒ with P0,1 = the pressure of 55.5 kPa
⇒ with P0,2 = the pressure of 28.9 kPa
(n-1) = (log (340/178)) / log( 28.9/55.5)
(n-1) = log (1.91) / log(0.52)
(n-1) = 0.281 / -0.284
n-1 = -1
n = 0
The order of this half-life reaction is zero. This is a zero order reaction.
