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In the diagram, the length of segment VS is 39 units.
What is the length of segment TV?
3x + 4
14 units
19 units
38 units
50 units
2x + 5
6x - 3
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calculista

Answer:

[tex]TV=38\ units[/tex]

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The figure shows a kite

The kite has two pairs of consecutive and congruent sides and the diagonals are perpendicular

That means

TS=VS

TQ=VQ

TR=RV

we have

[tex]VS=39\ units[/tex]

[tex]TS=6x-3[/tex]

so

[tex]6x-3=39[/tex]

solve for x

[tex]6x=39+3\\6x=42\\x=7[/tex]

Find the value of RV

[tex]RV=2x+5[/tex]

substitute the value of x

[tex]RV=2(7)+5=19\ units[/tex]

Remember that

[tex]TV=TR+RV[/tex] ---> by segment addition postulate

we have

[tex]TR=RV=19\ units[/tex]

so

[tex]TV=19+19=38\ units[/tex]

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