Answer:
current in the tube is 0.6A
Explanation:
Charged particles move in opposite directions, thus their contributions to total current are additive.
I = (3 × 10¹⁸ + 0.75 × 10¹⁸) * (1.6 × 10⁻¹⁹)
I = 0.6A
The current in the tube is 0.6A
Since In a fluorescent tube of diameter 3 cm, 3 times 1018 electrons and 0.75 times 1018 positive ions (with a charge of +e)
Since Charged particles move in opposite directions, so their contributions to total current are additive.
Now the current is
I = (3 × 10¹⁸ + 0.75 × 10¹⁸) * (1.6 × 10⁻¹⁹)
I = 0.6A
Learn more about current here: https://brainly.com/question/11311946
