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Triangle ABC is an isosceles triangle in which AB = AC. What is the perimeter of △ABC?
5 + square root of 10 units

3x square root of units

10 + square root of 10 units

15 units

Triangle ABC is an isosceles triangle in which AB AC What is the perimeter of ABC 5 square root of 10 units 3x square root of units 10 square root of 10 units 1 class=

Respuesta :

Louli
Answer:
perimeter = 10 + 
√10 units

Explanation:
First, we will need to get the length of each line using the distance formula which is as follows:
distance = 
[tex] \sqrt{( x_{2}- x_{1} )^2 + ( y_{2} - y_{1})^2 } [/tex]

1- length of AB:
AB = 
[tex] \sqrt{(-1--1)^2+(1-6)^2} [/tex] = 5 units

2- length of AC
length of AC is the same as AB = 5 units

3- length of BC:
BC = 
[tex] \sqrt{(2--1)^2+(2-1)^2} [/tex] = √10 units

Now, we can get the perimeter by adding the side lengths as follows:
perimeter = 5 + 5 + 
√10
perimeter = 10 + 
√10 units

Hope this helps :)

okie the answer is

10 + square root of 10 units