Answer:
1.52g
Explanation:
First, let us calculate the number of mole of CO2 present. This is illustrated below:
V = 800mL
Recall: 1000mL = 1L
800mL = 800/1000 = 0.8L
P = 94.5 KPa = 94500Pa
Recall: 101325Pa = 1atm
94500Pa = 94500/101325 = 0.93atm
T = -10°C = -10 + 273 = 263K
R = 0.082atm.L/Kmol
n =?
PV = nRT
n = PV/RT
n = (0.8x0.93)/(0.082x263)
n = 0.0345mol
Now, we can obtain the mass of CO2 as follows:
Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol
Number of mole of CO2 = 0.0345mol
Mass of CO2 = number of mole x molar Mass
Mass of CO2 = 0.0345 x 44 = 1.52g
