Answer:
The work and heat transfer for this process is = 270.588 kJ
Explanation:
Take properties of air from an ideal gas table. R = 0.287 kJ/kg-k
The Pressure-Volume relation is PV = C
T = C for isothermal process
Calculating for the work done in isothermal process
W = P₁V₁ [tex]ln[\frac{P_{1} }{P_{2} }][/tex]
= mRT₁[tex]ln[\frac{P_{1} }{P_{2} }][/tex] [∵pV = mRT]
= (5) (0.287) (272.039) [tex]ln[\frac{2.0}{1.0}][/tex]
= 270.588 kJ
Since the process is isothermal, Internal energy change is zero
ΔU = [tex]mc_{v}(T_{2} - T_{1} ) = 0[/tex]
From 1st law of thermodynamics
Q = ΔU + W
= 0 + 270.588
= 270.588 kJ
