Respuesta :
Answer:
Check Explanation.
Explanation:
For a simple pendulum, the period is given as
T = 2π√(L/g)
It is also given as
T = 2π√(m/k)
where
T = period of oscillation
m = mass of the pendulum
L = length
g = acceleration due to gravity
k = force constant
Equating this two equations,
2π√(L/g) = 2π√(m/k)
(L/g) = (m/k)
(m/L) = (k/g)
So, any pendulum that will have the same period as our pendulum with mass, m, and length, L, must have the ratio of (L/g) to be the same as the pendulum under consideration and the ratio of its mass to force constant (m/k) must also be equal to this ratio.
Hope this Helps!!!
Any pendulum that will have the same period with mass, m, and length, L, must have the ratio of (L/g) and the ratio of its mass to force constant (m/k) must also be equal to this ratio.
For a simple pendulum, the period is given as
[tex]\bold {T = 2\pi \sqrt{\dfrac L{g}}}[/tex]
This is also given as
[tex]\bold {T = 2\pi \sqrt{\dfrac m{k}}}[/tex]
where
T = period of oscillation
m = mass of the pendulum
L = length
g = acceleration due to gravity
k = force constant
Equate these equations,
[tex]\bold {T = 2\pi \sqrt{\dfrac L{g}}} = \bold {T = 2\pi \sqrt{\dfrac m{k}}}\\\\\bold {\bold { \dfrac L{g} = \dfrac m{k}}} }\\\\\bold {\bold { \dfrac m{L} = \dfrac k{g}}} }[/tex]
So, any pendulum that will have the same period with mass, m, and length, L, must have the ratio of (L/g) and the ratio of its mass to force constant (m/k) must also be equal to this ratio.
To know more about the period of pendulum,
https://brainly.com/question/21630902
