Answer:
Frequency, [tex]f=5.24\times 10^{14}\ Hz[/tex]
Explanation:
It is given that, a yellow laser provides 210 kJ/mol of energy to excite electrons in a sample. We need to find the frequency of this light.
Energy, E = 210 kJ/mol
i.e.
[tex]E=210\ \dfrac{kJ}{mol}\\\\E=210\times 1000\ \dfrac{J}{mol}\\\\E=\dfrac{21\times 10^4\ J/mol}{6.022\times 10^{23}\ /mol}\\\\E=3.48\times 10^{-19}\ J[/tex]
The energy used to excite electrons is given by :
[tex]E=hf\\\\f=\dfrac{E}{h}\\\\f=\dfrac{3.48\times 10^{-19}}{6.63\times 10^{-34}}\\\\f=5.24\times 10^{14}\ Hz[/tex]
