Answer:
The final volume of the metal and water is 54.46mL
Explanation:
Hello,
To solve this question, we'll first of all find the volume of the metal and assuming there's no loss of water by overflow in the container, we'll add the volume of the metal to the volume of the water to get the final volume.
Data;
Mass of the metal = 45.5g
Volume of the water = 45mL
Density of the metal (ρ) = 3.65g/mL
Density of the metal = mass / volume
ρ = mass / volume
Volume (v) = mass / density
Volume = 45.5 / 3.65
Volume = 12.46mL
The volume of the metal is 12.46mL.
When the metal is added to the container 45mL of water, assuming no water was lost by overflow in the container, the final volume =
Final volume = volume of metal + volume of water
Final volume = 12.46 + 45.0
Final volume = 57.46mL
The final volume of the metal and water is 57.46mL
