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Write the IUPAC and common names, if any, of the carboxylate salts produced in the reaction of each of the following carboxylic acids with NaOH: 2-methylhexanoic acid
Part A
2-bromopropanoic acid Spell out the full name of the compound. If there is a common name separate your answers by a comma.
Part B
2-methylhexanoic acid Spell out the full name of the compound. If there is a common name separate your answers by a comma.

Respuesta :

Answer:

Following are the explanation to this question:

Explanation:

The salts of carboxylate are named by the writing, which is also named as the creation of the first, which is followed by the name of the carboxylic acid were '-ic' of the acid end and replaced by the 'ate'.

Following are the description of the given reaction:

In reaction A:

2-Bromopropanoic acid= [tex]C_3H_5BrO_2[/tex]

[tex]C_3H_5BrO_2+NaOH[/tex]⇄ [tex]C_3H_4BrNaO_2 +H_2O[/tex]

The IUPAC name is Sodium-2-Bromopropanate

In reaction B:

2-Methylhexanoic acid= [tex]C_7H_{14}O_2[/tex]

[tex]C_7H_{14}O_2+NaOH[/tex]⇄ [tex]C_7H_{13}NaO_{2}+H_2O[/tex]

The IUPAC name is Sodium-2-Methyl hexanoate

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