For a function g(x), the difference quotient is 6^x+h+3 - 6^x+3 /h
What is the average rate of change of g(x) on the interval from x = –2 to x = 1?
A. 30
B. 36
C. 430
D. 1, 290

For a function gx the difference quotient is 6xh3 6x3 h What is the average rate of change of gx on the interval from x 2 to x 1 A 30 B 36 C 430 D 1 290 class=

Respuesta :

Answer:

30

Step-by-step explanation:

The average rate of change of g(x) on the interval from x = –2 to x = 1 is 430 option (C) is correct.

What is a function?

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We know the average rate of change can be evaluated using:

[tex]\rm Average = \dfrac{f(b) - f(a)}{b-a}[/tex]

Here the interval is [a, b]

As the quotient is given;

[tex]= \rm \dfrac{6^{x+h+3} - 6^{x+3}} {h}[/tex]

x = -2

x+h = 1

-2 + h = 1

h = 3

Put this values in the above quotient:

[tex]\rm = \rm \dfrac{6^{-2+3+3} - 6^{-2+3}} {3}[/tex]

After solving, we will get:

= 430

Thus, the average rate of change of g(x) on the interval from x = –2 to x = 1 is 430 option (C) is correct.

Learn more about the function here:

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