A bucket holds 8 5/8L of water. A third of the eater is poured out and 3/4L of water is poured back in. How many liters of water are now in the bucket?

Can you also explain how to get the answer (for brainliest) :>

If a bucket holds 8 5/8 of water and A third is poured out this will call for subtraction. Afterwards, three quarters is poured back in and this will call for addition.

Rather we can di the sum with the BODMAS way

This is where we will get the addition first and subtraction second. I'll illustrate...

WITHOUT BODMAS: 8 5/8-1/3+3/4

WITH BODMAS:8 5/8 +3/4 -1/3

After calculation we come with the conclusion that the answer is 9 1/24

A bucket holds 8 5/8L of water. A third of the eater is poured out and 3/4L of water is poured back in. How many liters of water are now in the bucket? Can you also explain how to get the answer (for brainliest) :>

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A bucket holds 8 5/8L of water. A third of the eater is poured out and 3/4L of water is poured back in. How many liters of water are now in the bucket?

Can you also explain how to get the answer (for brainliest) :>