Answer:
the average speed of [tex]V_{av} CO_2[/tex] is 5.24 × 104 cm/s
Explanation:
The computation of the average speed of a [tex]CO_2[/tex] is as follows:
[tex]\sqrt{average} = \sqrt{\frac{8 RT}{\pi M} }[/tex]
where,
M = Molar mass
[tex]V_{av} = \frac{\sqrt{1}}{M}[/tex]
Given that
[tex]V_{av} \ of\ oxygen= 6.14 \times 10^4 cm/s[/tex]
The molar mass of oxygen i.e. (MO_2) = 31.9988 g/mol
And, the molar mass of CO_2 is 44.0098 g/mol
Now
[tex]\frac{V_{av} CO_2}{V_{av} O_2} = \frac{\sqrt{M_{O2} }}{M_{CO2}}[/tex]
Now place these values to the above formula
[tex]\frac{V_{av}CO_2}{6.14\times 104 cm/s} = \frac{\sqrt{31.9988} }{44.0098}[/tex]
So,
V_av CO_2 is 5.24 × 104 cm/s
hence, the average speed of [tex]V_{av} CO_2[/tex] is 5.24 × 104 cm/s
