Answer:
A= 7
B= 8
C= 3
Step-by-step explanation:
For C: 9=C*C-->C=SQRT(9)=3
For B: Some number ending in 4 is equals to B*C, C being 3. Then, the first number that fits that criteria would be B=8, as B*C=8*3=24.
For C: Some number ending in 1 equals to A*C. Then, the first number that fits that criteria is A=7, as A*C=7*3=21.
If you now multiply ABC*ABC (783*783) you'll see that all the elements in the multiplication process as carried out in the pdf are non-zero, so our answer satisfies the conditions of the problem!
