Write an equation in point-slope form and slope-intercept form for a line passes through (0, 1) and (2, 5)
1-y - 5 = 2 ( x + 2 ) ; y= 2x - 1
2-y + 5 = 2 ( x - 2 ) ; y = 2x - 1
3-y - 2 = 5 ( x - 2 ) ; y=5x + 1
4-y - 5 = 2(x - 2) ; y = 2x + 1
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belgrad belgrad · Answer 1 · 2021-02-09T01:10:17+01:00

Answer:

4) y - 5 = 2 (x -2) ;y = 2 x +1

The equation of the straight line in point - slope form

y - 5 = 2 (x -2)

The equation of the straight line passing through the point (2,5) and having slope m=2

y = 2 x +1

Step-by-step explanation:

Step(i):-

Given that the points are (0,1) and (2,5)

Slope of the line

[tex]m = \frac{y_{2}-y_{1} }{x_{2} -x_{1} } = \frac{5-1}{2-0} = \frac{4}{2} = 2[/tex]

Step(ii):-

The equation of the straight line passing through the point (2,5) and having slope m=2

y - y₁ = m(x-x₁)

y - 5 = 2 (x -2)

y -5 = 2x - 4

y = 2x -4+5

y = 2 x +1

Final answer:-

The equation of the straight line in point - slope form

y - 5 = 2 (x -2)

The equation of the straight line passing through the point (2,5) and having slope m=2

y = 2 x +1