Answer: The velocity of the ball the ball after collision is 5.5 m/s.
Explanation:
John hitting the bottle which is at rest means this is an Elastic collision.
Mass of the ball= [tex]M_1=0.4 kg[/tex]
Velocity of ball before collision = [tex]U_1=18m/s[/tex]
Velocity of ball after collision =[tex]V_1[/tex]
Mass of the bottle= [tex]M_2=0.2 kg[/tex]
Velocity of bottle before collision = [tex]U_2=0 m/s[/tex](bottle is at at rest)
Velocity of bottle after collision =[tex]V_2=25 m/s[/tex]
[tex]M_1V_1+M_2V_2=M_1U_1+M_2U_2[/tex]
[tex]V_1=\frac{(0.4 kg\times 18 m/s+0.2 kg\times 0m/s)-0.2 kg\times 25m/s}{0.4}[/tex]
[tex]V_1=5.5 m/s[/tex]
The velocity of the ball the ball after collision is 5.5 m/s.
