The number of electrons running in a stream comprises the charge. The excess electrons on this balloon with the given charge are 2.9 × 10¹³.
The charge is the number of electrons flowing in the stream of current times the charge on that electrons.
Q= n×e
The charge on the electrons e =1.6×10⁻¹⁹ C and the given charge on the balloon is 3.5μC = 3.5×10⁻⁶ C
the number of the excess electrons will be
[tex]n=\dfrac{3.5\times10^{-6} C}{1.6\times10^{-19} C}=2.19\times10^{13}[/tex]
The excess electrons on this balloon with the given charge are 2.9 × 10¹³.
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