ANSWER
A. (243pi+162) ft^2
EXPLANATION
The area of the shaded region is the sum of the area of the major sector and the area of the isosceles triangle.
Area of major sector
[tex]=\frac{360-90}{360}[/tex] × [tex]\pi[/tex] × [tex]18^2[/tex]
[tex]=243\pi ft^2[/tex]
The area of the isosceles triangle is calculated using the formula;
[tex]=\frac{1}{2}r^2sin(0)[/tex]
[tex]=\frac{1}{2}[/tex] × [tex]18^2[/tex] [tex]sin(90)[/tex]
[tex]=162ft^2[/tex]
The area of the shaded region
[tex]=(243\pi +162)ft^2[/tex]
The correct answer is A.
