Respuesta :
Answer:
Step-by-step explanation:
Alright, lets get started.
Suppose car 2 overtakes car 1 at distance d in t hrs after car 1 moves.
So, distance covered by car 1 in t hrs will be :
[tex]distance = speed*time[/tex]
[tex]d=55*t = 55t[/tex]
distance covered by car 2 will take 4 minutes less that car 1, so time will be
[tex](t-\frac{4}{60})=(t-0.067)[/tex]
So, distance covered by car 2 will be:
[tex]d = 70*(t-0.067) = 70t - 4.69[/tex]
Both distance will be same for overtaking, so
[tex]55t = 70t-4.69[/tex]
[tex]15t = 4.69[/tex]
[tex]t =0.31 hrs[/tex]
It will take 0.31 hrs to overtake car 1 : Answer
Hope it will help :)
answer:
Average speed of Car 1 = 55 mph. Average speed of Car 2 = 70 mph. Time elapsed between start of Car 1 and start of Car 2 = 4 minutes. How long before Car 2 overtakes Car 1? hour = 0.24 hours
