Answer : [tex]a=10\ m/s^2[/tex]
Explanation :
It is given that,
Mass of the engine, m = 30 kg
Thrust is equivalent to the force acting perpendicularly and it is F = 300 N
According to Newton's second law of motion :
[tex]F = m\times a[/tex]
a is the acceleration of the engine.
[tex]a=\dfrac{F}{m}[/tex]
[tex]a=\dfrac{300\ N}{30\ Kg}[/tex]
[tex]a=10\ m/s^2[/tex]
So, the acceleration of the engine is [tex]10\ m/s^2[/tex].
Hence, this is the required solution.
Answer:
Acceleration, [tex]a=10\ m/s^2[/tex]
Explanation:
It is given that,
Mass of the cart, m = 30 kg
Thurst applied to the engine, F = 300 N
Let a is the acceleration of the cart. According to Newton's second law of motion, force is equal to the product of mass and acceleration. It is given by :
[tex]F=ma[/tex]
[tex]a=\dfrac{F}{m}[/tex]
[tex]a=\dfrac{300\ N}{30\ kg}[/tex]
[tex]a=10\ m/s^2[/tex]
So, the acceleration of the cart is [tex]10\ m/s^2[/tex]. Hence, this is the required solution.
