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A construction company needs 5 1/6 tons of dirt from a construction site. They can remove 5/9 tons of dirt each hour. What is the total number of hours it will take to remove the dirt ?

Respuesta :

One hour = 5/6 tons of dirt.

Number of hour needed to remove 5 1/6 tons of dirt:

[tex]5 \dfrac{1}{6} \div \dfrac{5}{6} [/tex]

Write in improper fraction:

[tex]=\dfrac{31}{6} \div \dfrac{5}{6} [/tex]

Change the divide fraction to multiplication fraction:

[tex]=\dfrac{31}{6} \times \dfrac{6}{5} [/tex]

Combine into single fraction:

[tex]=\dfrac{31}{5}[/tex]

[tex]=6\dfrac{1}{5} \text { hours }[/tex]
in 1 hr they can remove 5/6 amount of dirt

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