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Answer: 33.9 L of N₂ will react with 576.96 g (9.08 moles) of Cu.
I hope I helped
-Chris
Answer: 33.9 L of N₂ will react with 576.96 g (9.08 moles) of Cu.
I hope I helped
-Chris
Answer : The number of atoms of copper will be, [tex]54.67\times 10^{23}[/tex]
Solution :
As we know that 1 mole contains [tex]6.022\times 10^{23}[/tex] number of atoms
And,
At STP, 1 mole contains 22.4 liter volume of gas
First we have to calculate the moles of copper.
The balanced chemical reaction will be,
[tex]6Cu+N_2\rightarrow 2Cu_3N[/tex]
From the balanced chemical reaction we conclude that, 1 mole of nitrogen gas react with 6 moles of copper.
As, 22.4 L volume contains 6 moles of copper
So, 33.9 L volume contains [tex]\frac{6}{22.4}\times 33.9=9.08[/tex] moles of copper
Now we have to calculate the number of atoms of copper.
As, 1 mole of copper contains [tex]6.022\times 10^{23}[/tex] number of copper atoms
So, 9.08 moles of copper contains [tex]9.08\times (6.022\times 10^{23})=54.67\times 10^{23}[/tex] number of copper atoms
Therefore, the number of atoms of copper will be, [tex]54.67\times 10^{23}[/tex]
